4/3x^2-88=20

Solution for 4/3x^2-88=20 equation:

4/3x^2-88=20

We move all terms to the left:

4/3x^2-88-(20)=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

4/3x^2-108=0

We multiply all the terms by the denominator


-108*3x^2+4=0

Wy multiply elements

-324x^2+4=0

a = -324; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-324)·4
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-324}=\frac{-72}{-648}
=1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-324}=\frac{72}{-648}
=-1/9
$